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Mathematics 21 Online
OpenStudy (anonymous):

The lengths of randomly selected taxicab rides, in minutes, from a certain airport, are shown. 14 21 33 18 5 27 20 20 15 16 35 9 4 19 9 17 19 Which measure or measures of central tendency best reflect the data? Choose all answers that are correct. mean median mode

OpenStudy (perl):

first sort them in order

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

4, 5, 9, 9, 14, 15, 16, 17, 18, 19, 19, 20, 20, 21, 27, 33, 35

OpenStudy (perl):

Now lets identify, the mean, the mode, and the median.

OpenStudy (perl):

the mean is the arithmetic average of the values, add them all up divide by the number

OpenStudy (anonymous):

mean=average of all the numbers mode= the number that appears most often median= middle number sorry i took so long i had to look up mean

OpenStudy (perl):

right

OpenStudy (anonymous):

what is the questions asking? i dont really understand it.

OpenStudy (perl):

It is asking, of those three options, mean median or mode, which one best represents the 'center' of the taxicab length of ride

OpenStudy (anonymous):

oh median

OpenStudy (perl):

what is a typical length of ride from the airport, from those selected data values

OpenStudy (perl):

median and mean are pretty close in this example

OpenStudy (anonymous):

18

OpenStudy (perl):

we use the median usually in the case when there are outliers. otherwise we use the mean

OpenStudy (perl):

either one is fine,

OpenStudy (perl):

mean and median are very close

OpenStudy (perl):

mean and median. but not mode, do you see why not mode?

OpenStudy (anonymous):

yes, because is 19, and 20....which is not 18. and 18 is how long a typical taxi cab ride to the airport is.

OpenStudy (perl):

right, this data set does not have a single mode, so its not useful

OpenStudy (anonymous):

it can be more than one option, so mean and median

OpenStudy (perl):

right

OpenStudy (perl):

http://prntscr.com/70w9te

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