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If \(x+y=5\) and \(x-y=3\), then \(x^2-y^2=\) 9 15 16 25 34
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Note that \[(a-b)(a+b)=a^2-b^2\]
Yes.
ok, so what's \(x+y\) ?
I'm not sure..
it's given in the problem
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Oh, 5.
right what is \(x-y\) ?
3
good now, given that \((x-y)(x+y)=x^2-y^2\), what is \(x^2-y^2\) ?
So, \(5 * 3\) = \(5^2-3^2\)=25-9=16
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no, on the left side you substituted correctly, then you decided to make x=5 and y=3 for some reason
So just, \(5*3\)
yep
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