Question

What is the fourth term in this multiplication pattern?

multiplication pattern using the formula 2 • 6n – 1

A.
2592

B.
12

C.
432

D.
72

Answer 1

help plz

Answer 2

Is 6n really 6n or is it \(6^n\)?

Answer 3

6^n

Answer 4

Or is the whole thing \(2 \times 6^{n - 1}\)

Answer 5

yes

Answer 6

Ok, I think I understand it now.
The problem uses the exponent n - 1 and is
\(2 \times 6^{n - 1} \)
You need th e4th term, so you need to evaluate this expression when n = 4:

\(2 \times 6^{4 - 1} = 2 \times 6^3 = 2 \times 216 = 432\)

Answer 7

oh now i get it so you subtract on from ^4 ^3 thank you i will fan and medal

Answer 8

Yes. The exponent is n - 1, so since you need the 4th term, when n = 4, the exponent becomes 4 - 1 = 3. Then you raise 6 to the 3rd power, and finally you multiply it by 2.

Answer 9

You're welcome.