please help :( can someone please solve and graph |2x-5|+3 less than or equal to 10
You need to solve it by graphing?
Nopee i need to solve then graph
Okay, Best thing to do first is to isolate absolute value, right? Just subtract both sides by 3, then you should have \(|2x-5|\le7\). Any idea on how to get rid of absolute value?
i think i add and subtract 5?
Well, that won't help get rid of it, though. \[|2x-5|+5\le12\]
i thought i leave the equation as it is after subtracting 3. and then solve it but also do another equation with 2x+5
Yeah kind of. Let just say \(2x+5 =a\) So here you have \(|a|\le7\). Do you know what value \(a\) only can be?
7
?
Well, yeah \(7\le7\) But there are more, right? what about 6? 5? and so on?
Until 0?
Can we go behind 0 to negative number?
How far can we go?
oh ok well i really just need help on this specific problem being that i have many more to do due by 10
Well, I'm just trying to help you understand how to solve it, so you don't have to ask similar questions again and again.
of course thanks
But if you need answer for grade sake, well, sorry to say but we aren't allowed to do that lol...
Can you spare time?
that isnt what i was asking for
Okay, back to stuffs. \(|a|\le7\) What range of number can \(a\) be?
It only can goes from 7 to -7, right?
Because \(|-7.1|\le7\) isn't correct, right?
So you can "translate" \(|a|\le 7\) to \(-7\le a\le7\) Makes sense so far?
mhmm
So here \(|2x-5|\le 7\quad\Longrightarrow\quad -7\le2x-5\le 7\)
Now you can do algebra from here
idk how to graph x\[x \le6,1\]
How did you get to \(x\le6,1\)?
i solved it dude
im sorry i dont have time for a lesson at the moment so im trying to rush and use prior knowledge
It's \(-1\le x\le 6\) This mean x can only be in between -1 to 6 inclusive. So you can graph like this:|dw:1430703011919:dw|
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