algebra help (solving for a and b)
i am stuck on the algebra in a calculus problem
32= A(2k+1) + B(2k-1)
32= A2k + A + B2k - B
32= 2k(A+B) + (A-B)

here is where im stuck
i say 0 = A + B
and 32 = A-B

but its not right

Question

algebra help (solving for a and b)
i am stuck on the algebra in a calculus problem
32= A(2k+1) + B(2k-1)
32= A2k + A + B2k - B
32= 2k(A+B) + (A-B)

here is where im stuck
i say 0 = A + B
and 32 = A-B

but its not right

isaiah.feynman · Answer

Look at the (2k-1) and (2k+1), do they remind you of anything?

anonymous · Answer

no.

anonymous · Answer

i distribute everything out and then im collecting like terms

anonymous · Answer

he might be talking about (x-1)(x+1)=(x^2-1) i believe but i dont think that will work

anonymous · Answer

@arturos your probably right, and your correct it doesnt help in this situation

anonymous · Answer

but i might be wrong

anonymous · Answer

what is k

isaiah.feynman · Answer

Only way I see here is to solve for A+B

anonymous · Answer

Isaiah is right
you will probably have to isolate A then b with expanding

anonymous · Answer

a variable. $$32/((2k-1)(2k+1)) = A/(2k-1) + B/(2k+1)$$

isaiah.feynman · Answer

I don't understand. @clickspiker23

anonymous · Answer

WOW. ok so 0=A+B 
so B=-A
which makes 32 = A-(-A0
32=2A
A=16
B=-16

anonymous · Answer

which is the correct answer. Its been a long day

anonymous · Answer

yup
all Isaiah

isaiah.feynman · Answer

Okay. That part was straight forward. I didn't look at it actually.

anonymous · Answer

im solving a telescoping series question

anonymous · Answer

thanks @Isaiah.Feynman and @arturos

anonymous · Answer

np