What is the distance between points (4, −7) and (−5, 9)? Round to the nearest tenth of a unit. --- units
Plot the points first. Find the horizontal and vertical displacement from one point to another and then use the Pythagorean Formula.
\(\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 4}}\quad ,&{\color{blue}{ -7}})\quad % (c,d) &({\color{red}{ -5}}\quad ,&{\color{blue}{ 9}}) \end{array}\qquad % distance value d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)
the answer is rounded to about 18.36
and no u dont u tht @jdoe0001
u use the process of Pythagorean therom
@kandy=D would it be 18.4? due to rounding the 6 to the nearest tenth
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