Question

The number of loops in the primary coil divided by the number of loops in the secondary coil equals
the voltage in the primary coil divided by the voltage in the secondary coil. If the voltmeter attached
to the primary coil read 100 volts, what would the voltmeter attached to the secondary coil read?"

Coil A (secondary)= 600 coils
Coil B (primary)= 300 coils

Answer 1

@EclipsedStar

Answer 2

#loops1primary/#loops2secondairy=v1primary/v2secondary
300/600=100/x

Answer 3

\[\frac{ primaryloop }{ secondairyloop } =\frac{ Vprimary }{Vsecondary}\]

Answer 4

The above solution is right

Answer 5

I m now telling u same thing in a little different way

Answer 6

E1/E2=N1/N2

Answer 7

100/E2=300/600
E2=?

Answer 8

Response plz!

Answer 9

It's 200, I figured it out, sorry I forgot to close the question