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I believe so yes
If you look at what angle side side is, you're given an angle |dw:1430802392602:dw|
A side |dw:1430802448286:dw|
And another side. We know the length of the last side, but not it's angle, so imagine a circle of options of where it could "land" |dw:1430802490928:dw|
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So there are two options there. Since it's impossible for a line to intersect a circle 3 times, it's at most 2 possible triangles.
If it's a right angle it would be 1 possible solution, as the two triangles would "meet" when you pull the angle back if that makes sense.
Does that make sense?
It's possible for there to be an invalid triangle, b|dw:1430802871467:dw|
Ok, thank you
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