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Mathematics 22 Online
OpenStudy (anonymous):

8th grade please help me and explain how to find answer How many combinations of 3 students can a teacher choose from 32 students? A. 4960 B. 29,760 C. 32,768 D. 96

OpenStudy (anonymous):

@TrevorBaker @G_Osmenaj

OpenStudy (anonymous):

32*31*30 -------- 3*2*1

OpenStudy (anonymous):

= 32*31*5

OpenStudy (g_osmenaj):

I agree with @israa88

OpenStudy (g_osmenaj):

B

OpenStudy (anonymous):

im sorry I feel like a idiot but im kinda confused? so sorry

OpenStudy (anonymous):

its ok

OpenStudy (anonymous):

32*31*30 -------- 3*2*1 solve this

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

so multiply 32 * 31 and 30 = 29760 divide that by 6 which is 4960

OpenStudy (anonymous):

29760 ------- 6?

OpenStudy (anonymous):

yup ur doing it right now after u divide u get 4960

OpenStudy (anonymous):

oohh okay thank you sooo much! :)

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

so u get it now ?

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