Mathematics
7 Online
OpenStudy (butterflydreamer):
Growth and Decay question.
I need help with part B :) Thaaaank you !
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OpenStudy (surana):
Try doubling the values. I think.
OpenStudy (acxbox22):
graph it on a graphing calculator first
OpenStudy (surana):
Desmos Graphing Calculator is a good place to start. Try it.
OpenStudy (butterflydreamer):
I've already graphed it :)
OpenStudy (anonymous):
¿Hablas chicos españoles ?
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OpenStudy (surana):
Excellent, what did you get?
OpenStudy (surana):
Hola senor, como esta usted?
OpenStudy (anonymous):
bien cómo estas?
OpenStudy (butterflydreamer):
umm.. A = 100 when t = 0?
OpenStudy (surana):
Bien, gracias.
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OpenStudy (anonymous):
te gusta ayudar a las personas con las matemáticas ?
OpenStudy (butterflydreamer):
oops. I get it now!
k = 0.1 ^_^
OpenStudy (surana):
Yo tambien.
OpenStudy (surana):
That's good, butterflydreamer!
OpenStudy (dan815):
i dont get it, why is it 0.1
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OpenStudy (dan815):
this question looks weird, the area is never twice its initial value though
OpenStudy (surana):
Honestly, I don't know. What's your perspective?
OpenStudy (surana):
Is that a good or bad thing?
OpenStudy (rational):
initial value is 100
limiting value is 300
so there exists a value 200 somewhere in between right ?
OpenStudy (dan815):
oh 300 is limit? i thought it was decaying
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OpenStudy (surana):
Probably.
OpenStudy (rational):
subtracting a decaying function from a big positive value gives an increasing function
OpenStudy (surana):
Okay.
OpenStudy (dan815):
oops lol wasnt thinking
OpenStudy (dan815):
at t=inf we got A=300 ofcourse
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OpenStudy (dan815):
would we have to solve these system of eqn then
\[dA/dt=10\\
200=300*(1-2/3 * e^{-kt})\]
OpenStudy (rational):
yes k=0.1 is right
OpenStudy (dan815):
i concur