Question

1+(1/2)+(1/4)+(1/8)+(1/16)+(1/32)+(1/64)=?????

Answer 1

\[\sum_{1}^{7}2^{1-n}\]

Answer 2

Just add them up. If you're lazy, you can use the shortcut for a little less work

Answer 3

@larryboxaplenty , can u explain this method to me plz?

Answer 4

My first comment is sigma notation. Find the sum from n= 1 to 7, of 2^(1-n). Let n=1, and you get 1, let n=2 and you get 0.5, for n=3 you get 1/4. You get the sequence of your question

Answer 5

makes sense thanks!

Answer 6

1 and 63/64