Mathematics
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OpenStudy (anonymous):
What is the scale factor for the set of similar figures?
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OpenStudy (anonymous):
OpenStudy (anonymous):
Since the first image is contracting to the second image it will be 20/7.
OpenStudy (anonymous):
do u hv to round ur answer?
OpenStudy (anonymous):
I don't know it doesn't say
OpenStudy (anonymous):
I'm going to say yeah though
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OpenStudy (anonymous):
well the answer is pretty big so im assuming u need to round
OpenStudy (anonymous):
So 2.86?
OpenStudy (anonymous):
If you round your answer to the nearest tenth it will be 2.86
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Yep :)
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OpenStudy (anonymous):
Ok I have another one. Same question different set of figures.
OpenStudy (anonymous):
That looks exactly the same as the question before.
OpenStudy (anonymous):
Oh oops wrong picture
OpenStudy (anonymous):
divide those 2 numbers
OpenStudy (anonymous):
pretty much the same method as before
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OpenStudy (anonymous):
This time we're expanding so it will be 9.6/6.
OpenStudy (anonymous):
When I divide I get 0.625, but the test only lets me input a certain amount of numbers and it stops me at 0.62.
OpenStudy (anonymous):
9.6/6 = 1.6
OpenStudy (anonymous):
Ohh. I thought I had to do 6/9.6
OpenStudy (anonymous):
Yea, I guessed that :)
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OpenStudy (anonymous):
yea y not thts wat i thought
OpenStudy (anonymous):
Thanks I got it. :)
OpenStudy (anonymous):
I'm glad!