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Mathematics 13 Online
OpenStudy (anonymous):

What is the scale factor for the set of similar figures?

OpenStudy (anonymous):

OpenStudy (anonymous):

Since the first image is contracting to the second image it will be 20/7.

OpenStudy (anonymous):

do u hv to round ur answer?

OpenStudy (anonymous):

I don't know it doesn't say

OpenStudy (anonymous):

I'm going to say yeah though

OpenStudy (anonymous):

well the answer is pretty big so im assuming u need to round

OpenStudy (anonymous):

So 2.86?

OpenStudy (anonymous):

If you round your answer to the nearest tenth it will be 2.86

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Yep :)

OpenStudy (anonymous):

Ok I have another one. Same question different set of figures.

OpenStudy (anonymous):

That looks exactly the same as the question before.

OpenStudy (anonymous):

Oh oops wrong picture

OpenStudy (anonymous):

divide those 2 numbers

OpenStudy (anonymous):

pretty much the same method as before

OpenStudy (anonymous):

This time we're expanding so it will be 9.6/6.

OpenStudy (anonymous):

When I divide I get 0.625, but the test only lets me input a certain amount of numbers and it stops me at 0.62.

OpenStudy (anonymous):

9.6/6 = 1.6

OpenStudy (anonymous):

Ohh. I thought I had to do 6/9.6

OpenStudy (anonymous):

Yea, I guessed that :)

OpenStudy (anonymous):

yea y not thts wat i thought

OpenStudy (anonymous):

Thanks I got it. :)

OpenStudy (anonymous):

I'm glad!

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