Question

What are the first four terms in the multiplication pattern given by the formula?

3 · 6n
A.
9, 15, 21, 27

B.
18, 24, 30, 36

C.
18, 54, 162, 486

D.
18, 108, 648, 3888

Answer 1

Is that supposed to be \(3*6^n\)?
If so, then all you need to do is assume that 'n' is 1,2,3, and 4 for the first four terms. Then multiply \(3*6^1\), \(3*6^2\), etc to get your terms.