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A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 3y + 4z = 1 Which of the following is a possible step used in eliminating the y-term? A.(y + z = 6) ⋅ 4 B. (3y + 4z = 1) ⋅ 4 C. (y + z = 6) ⋅ −3 D.(3y + 4z = 1) ⋅ 3
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What do you think the answer is?
If you want to eliminate 3y, what would you multiply y by?
\(\large { \begin{array}{cllll} {\color{brown}{ y}} + z = 6\\ 3y + 4z = 1 \\\hline\\ 0 +\square =\square \end{array} }\) so as 10115658 said what would you need, to multiply "y", in order that its sum to "3y" below it gives 0?
what happens if you multiply the first equation by -3
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