Question

Solve for x

Answer 1

\[\sqrt{x +1} + \sqrt{x + 2} = 1\]

Answer 2

so far I have

\[\sqrt{x + 2} = 1 - \sqrt{x + 1} \]

Then I squared both sides

so now

\[x + 2 = 1 - 2\sqrt{x + 1} + x + 1\]

Answer 3

square both sides by 2 to get rid of your radical

Answer 4

or square root

Answer 5

so far I have

\[\sqrt{x + 2} = 1 - \sqrt{x + 1} \]

Then I squared both sides

so now

\[x + 2 = 1 - 2\sqrt{x + 1} + x + 1\]

Answer 6

if you square one side both of the roots are gone

Answer 7

it applies to both sides for what you do to one

Answer 8

but I did (a - b)^2 which gives you a^2 - 2ab + b^2

Answer 9

so x+2=1-x+1 i believe

Answer 10

what subject is this ?

Answer 11

Pre-Calculus

Answer 12

i thought so

Answer 13

im in calculus

Answer 14

add x to both sides then subtract 2 from both sides

Answer 15

Where do I add x? I don't have any negative x's

Answer 16

look at left side 1-x+1

Answer 17

*right side srry

Answer 18

Ohh that's where I messed up. I put + x + 1 instead of - x + 1

Answer 19

x+2=1-x+1

Answer 20

yeh it ok when i was learning this is took me 3 days to get so

Answer 21

k so you should get 2x=0 ???

Answer 22

I got 2x = \[-2\sqrt{x + 1}\]

Answer 23

i see when you square one side to eliminate the square root on one it also eliminates the other

Answer 24

its tricky

Answer 25

Im' really confused honestly

Answer 26

at the beginning when you squared one side right ?

Answer 27

you have to square both

Answer 28

Question: Why don't you let it as it is and square both sides? @Lifel
1^2 =1 @jakashaka

Answer 29

thats what i was trying to say

Answer 30

and its @jakashaka123 thanks you

Answer 31

I don't know where you guys are at

Answer 32

At the beginning

Answer 33

yep

Answer 34

beginning as in the very start of the problem?

Answer 35

square both sides to get rid of your stupid root symbols

Answer 36

yup @LifeIsADangerousGame

Answer 37

what you do to one side multiply / divide you do to the other the same way

Answer 38

it only applies to add - subtract when you do opposite

Answer 39

Okay. but if I square both sides without doing anything, won't I get something like
\[\ 2x + 3 + sqrt{(x+1)(x+2} + \sqrt{(x+2)(x+1}\]

Answer 40

you want one square root symbol on one side only if its on 2 you have to move it

Answer 41

if 2 are on 1 side move it

Answer 42

Okay so then I moved sqrt(x + 1) over

so now it's sqrt(x + 2) = 1 - sqrt(x + 1)

Then I square both sides and get

x + 2 = 1 - 2sqrt(x+1) + x + 1 right?

Answer 43

there should be no more sqrt's