A bag contains 4 yellow marbles and 6 green marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then a second marble is drawn. What is the probability that the first marble is green and the second one is yellow?

Question

anonymous · Answer

What's P(1st marble green)?

1dfanatic · Answer

1/6

anonymous · Answer

6 green marbles and ten marbles total

anonymous · Answer

so 6/10

1dfanatic · Answer

but you didn't put one back to wouldn't it be 9?

anonymous · Answer

For the first pick it's 6/10. For the 2nd pick, the denominator is 9

anonymous · Answer

Is that what you were asking?

1dfanatic · Answer

yeah cx

1dfanatic · Answer

for the second pick wouldnt we do the yellow? i'm so confused..

anonymous · Answer

Yes the yellow. So what would that fraction be?

1dfanatic · Answer

4/9

anonymous · Answer

Yes. Now multiply them to get the answer

1dfanatic · Answer

4/15 cx thank you for your help these confuse me alot if you havent noticed.

anonymous · Answer

That's right. Yeah I'm not a fan of statistics either.