Question

find the ratio between the two numbers (image attached)

Answer 1

i get one part \[\frac{k-1}{1-k}=-1\]

Answer 2

now for
\[\frac{\ln(6^{\frac{1}{2}})}{\ln(6^{-1})}\]that should not be too hard right?

Answer 3

pull out the exponents as multiplyers, the cancel the \(\ln(6)\) part

Answer 4

@satellite73 thank you so much for breaking it down!! I see it now!