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Mathematics 21 Online
OpenStudy (anonymous):

Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation: C(x) = 2x2 - 40x + 300 C(x) is the cost in dollars of selling x sandwiches.

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

Which statement best compares the minimum daily cost of making burgers and sandwiches? It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches. It is greater for sandwiches than burgers because the approximate minimum cost is $100 for burgers and $295 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches.

OpenStudy (phi):

this one takes some thinking.

OpenStudy (anonymous):

yeah i dont really understnad what to do

OpenStudy (phi):

First step is read it, and try to make sense (going on the theory it must mean something)

OpenStudy (phi):

Look at this part. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. can you translate that into an equation ?

OpenStudy (anonymous):

uhmm idk how.i know the 30 is gonna have 30x+520 or something like that

OpenStudy (anonymous):

x^2-30x+520?

OpenStudy (anonymous):

So my brother kinda explained it and i got the answer D

OpenStudy (phi):

yes looks good to avoid confusion, let's use b instead of x cost(b) = b^2 -30b+520

OpenStudy (anonymous):

okay.

OpenStudy (phi):

forget that, because using b instead of x means I can't write down ax + bx + c and use -b/(2a) to find the min so find the min number of burgers by find the x value of the vertex of the equation x^2-30x+520

OpenStudy (anonymous):

is gonna be -30 and 520 correct?

OpenStudy (anonymous):

17

OpenStudy (phi):

a is in front of the x^2 and b is in front of the x (c is +520)

OpenStudy (anonymous):

so x and-30 how do i use that into -b/2a

OpenStudy (phi):

not x, we want only the numbers. remember x^2 is short for 1*x^2

OpenStudy (anonymous):

so its gonna be -30/2?

OpenStudy (anonymous):

then its gonna be -15?

OpenStudy (phi):

b is -30 -b is 30 so 15

OpenStudy (anonymous):

ohhh okay i got it

OpenStudy (phi):

15 burgers is where the cost is a min. to find the cost of 15 burgers we use the formula x^2-30x+520 with x= 15

OpenStudy (anonymous):

225-450+520

OpenStudy (anonymous):

scratch that 295

OpenStudy (phi):

so the min cost of the burgers is 295 that is enough info to answer the question but we could double check, and find the min cost of the sandwiches, using C(x) = 2x^2 - 40x + 300

OpenStudy (anonymous):

C i mean

OpenStudy (phi):

yes. And if you have time and are not lazy (a bad habit), you would check to see what number you get for the sandwiches. Same idea -b/(2a) to find x.

OpenStudy (anonymous):

okay so its gonna be 10 for x

OpenStudy (phi):

and figure out the cost of 10 sandwiches

OpenStudy (anonymous):

so its 100

OpenStudy (anonymous):

200-400+300

OpenStudy (anonymous):

can you check another questions answer for me please i got it i think but i just need to double check sorry if im bothering you.

OpenStudy (phi):

yes, which is a double check on choice C. (and good practice)

OpenStudy (phi):

what is the question?

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