If -nx2 + tx + c = 0, what is x equal to? x is equal to minus t plus or minus square root of t squared minus 4 multiplied by n multiplied by c, all divided by minus 2 times n x is equal to t plus or minus square root of t squared plus 4 multiplied by n multiplied by c, all divided by minus 2 times n x is equal to t plus or minus square root of t squared minus 4 multiplied by n multiplied by c, all divided by minus 2 times n x is equal to minus t plus or minus square root of t squared plus 4 multiplied by n multiplied by c, all divided by minus 2 times n
The answer is A
@phi
x=-t+-square root t^2-4ac/-2n is that correct?
it's hard to read equations written out in words. but the formula to find x so that \[ a x^2 + bx + c=0 \] is \[ \frac{1}{2a} \left(-b \pm \sqrt{b^2 -4ac} \right)\]
be careful about the signs. what is a, b and c in your problem ?
that the thing idk
i just looked at the quadratic formula and that is it.
\[ -nx^2 + tx + c = 0 \] what is "a" ?
-n
ok, and b is t and c is c use a= -n, b= t and c=c in the quadratic formula.
ohh so its D
x=-t+-square root t^2+4ac/-2n
4nc i ment
yes
the - 4(-n)c becomes +4nc
if you see -x^2 -2x -3 that means -1*x^2 + -2*x + -3 and a = -1, b=-2 and c= -3
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