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can someone help me on 2 sqrt 2 sin (theta) +2=0
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\[2 \sqrt{2 \sin \theta} + 2 = 0\] or \[2 \sqrt{2} \sin \theta + 2 = 0\]
the second one
How do you think you should start?
I really dont know lol but i normally factor it out
You could factor out a 2 first. But here you want to subtract the 2 first, then divide by 2√2
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so 2 sqrt 2 theta -2 = 0
Subtract the 2 from both sides of the equation
(2 √2) sin Θ = -2
then factor?
Then divide by 2√2
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You don't have to factor this equation at all
sin theta = -1
Sorry I got kicked out & now experiencing a lot of lag...
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