I WILL MEDAL!! Brian has a bag that contains 14 red marbles and 12 yellow marbles. He selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Brian selects a red marble and then a yellow marble? Round your answer to the nearest percent. P(red and yellow) ≈ %
You need to find the ratio and turn it into a percentage so you have 14 red and 12 yellow, Do you know what the ratio for the marbles?
is simply a case of P(red) x P(yellow) but remember when you select the 2nd marble there is 1 less to choose from
is it 14/26 * 12/25
that's correct, when you get the answer convert it to a percentage
@campbell_st is the answer 20%
well its 168/650 x 100 =
I'd say slightly higher
25.8%
makes sense
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