find the 6th term of the sequence: 8, 32, 128

Question

anonymous · Answer

8,192

anonymous · Answer

Look at the relation between each term. You'll notice that each term is the one before it multiplied by 4. What formula do you have that helps with this problem with given information?

anonymous · Answer

@ArtemisWolf - pls don't give direct answers, you are supposed to help and guide other users through their problems until they get it and find an answer

anonymous · Answer

|dw:1431116727195:dw|

anonymous · Answer

an is the number of term n (in this case, term 6). N is the term number (aka 6). r is the factor between each term (see my last post). a1 is the first term,

anonymous · Answer

$$a_{n}=ar^{n-1}$$
a=first term
r=common ratio
n=no of terms (it's 6 in your case)