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Mathematics 18 Online
OpenStudy (anonymous97):

find the 6th term of the sequence: 8, 32, 128

OpenStudy (anonymous):

8,192

OpenStudy (anonymous):

Look at the relation between each term. You'll notice that each term is the one before it multiplied by 4. What formula do you have that helps with this problem with given information?

OpenStudy (anonymous):

@ArtemisWolf - pls don't give direct answers, you are supposed to help and guide other users through their problems until they get it and find an answer

OpenStudy (anonymous):

|dw:1431116727195:dw|

OpenStudy (anonymous):

an is the number of term n (in this case, term 6). N is the term number (aka 6). r is the factor between each term (see my last post). a1 is the first term,

OpenStudy (anonymous):

\[a_{n}=ar^{n-1}\] a=first term r=common ratio n=no of terms (it's 6 in your case)

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