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Geometry 8 Online
OpenStudy (kitkats):

I am trying to find the angle that's in red in the picture in the comment. The area of circle P = 226.98 The area of sector APB = 40.98

OpenStudy (kitkats):

OpenStudy (loser66):

oh, I thought you throw the problem here to get the free answer so that I deleted my comment. Sorry. Just subtract them.

OpenStudy (kitkats):

I'm trying to find the angle, not the area

jimthompson5910 (jim_thompson5910):

what is the fraction that the sector takes up in terms of the entire circle?

OpenStudy (kitkats):

It doesn't have the fraction of the sector

jimthompson5910 (jim_thompson5910):

(area of sector)/(area of entire circle) = ???

OpenStudy (loser66):

Big area + small area = area of the whole circle = \(r^2*\pi\), where r is radius of the circle. Hence \(r^2={(226.98+40.98)/\pi}\) . You calculate it. Apply formula of area of a circle segment: \(area = \pi r^2*\dfrac{angle}{360}\) to find the angle

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