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OpenStudy (anonymous):

imagine you are the owner of a pizza shop that offers three different types of crusts, seven different toppings, and three different cheeses. Create an advertisement for your shop listing all the choices you offer and advertising a three-topping pizza with one type of cheese for $9.99How many different combinations of 1 crust, 3 different toppings, and 1 cheese does your shop offer?Of the possible combinations you offer, which is your favorite?What is the probability that a person would order your favorite pizza at random?

OpenStudy (amistre64):

what are your thoughts?

OpenStudy (anonymous):

I'm soooo lost

OpenStudy (amistre64):

3 choose 1 7 choose 3 and 3 choose 1 right?

OpenStudy (amistre64):

3 crusts; 3 choose 1 ways to order 1 crust 7 toppings; 7 choose 3 ways to order 3 different toppings 3 cheeses; 3 choose 1 ways to order 1 cheese

OpenStudy (amistre64):

how do we calculate these?

OpenStudy (amistre64):

crusts: a,b,c we can order a, b, or c ... 3 ways to order a crust ------------------------- cheese, x,y,z ; combine with the crusts gives us ax, bx, cx, ay, by, cy, az, bz, cz we can order 3 crusts and 3 cheeses in 9 different ways \[\binom31\binom31=9\] \[\binom31\binom31\binom73=?\]

OpenStudy (amistre64):

its a brute to try to define all the ways to order 3 toppings out of 7, which is why we have a formula to help out \[\binom nk=\frac{n!}{k!(n-k)!}\]

OpenStudy (amistre64):

ive got to go, but these are the basics for you

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