Question

Which of the following is a solution of 3x2 = 7x - 3?

Answer 1

A. \[\frac{ -7\pm \sqrt{13} }{6 }\]
B. \[\frac{ 7\pm \sqrt{85} }{6 }\]
C. \[\frac{ -7\pm \sqrt{85} }{6 }\]
D. \[\frac{ 7\pm \sqrt{13} }{6 }\]

Answer 2

We need an abc value first turn this into standard form

Answer 3

I don't know how to do that. Can you help me?

Answer 4

Ok this is standard form
\[ax^2+bx+c=0\]

Answer 5

here you will need to subtract 3x^2

Answer 6

what will your equation look like now?

Answer 7

\[0 = 7x -3 - 3x^2\]

Answer 8

@kidrah69

Answer 9

Ok so now what are your abc values?

Answer 10

a=3 b=7 and c =-3

Answer 11

nope

Answer 12

oops. a=-3 too

Answer 13

yep

Answer 14

oh

Answer 15

relist the abc values now :)

Answer 16

\[x= \frac{ -b ± \sqrt(b^2 - 4ac) }{ 2a }\]

Answer 17

Thats the quadratic formula

Answer 18

Now all we do is plug in the values

Answer 19

Here since you may not know how...
\[x= \frac{ -(7) ± \sqrt((7)^2 - 4(-3)(-3)) }{ 2(-3) }\]

Answer 20

The rest you just have to solve

Answer 21

Ok. I'll try to simplify. If I have a hang up can I tag you?

Answer 22

yes :)

Answer 23

Ok. So I solved that one but I'm stuck on another.

Answer 24

I've gotten to the point of \[x = \frac{ -8\pm \sqrt{120} }{ 4 }\]

Answer 25

Ok wait the c value is positive

Answer 26

give me a oment i will type in the work

Answer 27

But the choices are \[-2 \pm \sqrt{2}\]
\[-2 \pm2\sqrt{2}\]

Answer 28

and 2 others. how do i simplify further

Answer 29

http://prntscr.com/73fifz

Answer 30

get it?

Answer 31

I get it but it's telling me that I need to simplify more. I don't know where to go.

Answer 32

@kidrah69

Answer 33

hmmm

Answer 34

Oh you need to solve it too?

Answer 35

The original was 7+2x^2 - 8x = 0

Answer 36

After using the quadratic formula I got \[x = \frac{ -8\pm \sqrt{120} }{ 4 } \]

Answer 37

Why didnt you post that?

Answer 38

Whats the origional problem? :/

Answer 39

One sec. Lemme start in a new question to start over and so that I can give you another best response.