The value of y varies directly with x2, and y = 36 when x = 3.
What is the value of y when x = 5?
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OpenStudy (anonymous):
@TheSmartOne
OpenStudy (anonymous):
@amistre64
OpenStudy (amistre64):
whats your direct variation setup?
OpenStudy (anonymous):
Is it y=5? im lost
OpenStudy (amistre64):
it would be useful to start at the beginning so that we have a firm grasp on how to obtian a solution.
how do we set it up?
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OpenStudy (anonymous):
y=x5 ?
OpenStudy (amistre64):
direct variation means that when y increases, x increases .... y = kx^2
another way of writing this is ...
y/x^2 is constant for all (x,y)
36/3^2 = y/5^2
what is y?
OpenStudy (anonymous):
I got 4 by dividing 36 by 9
OpenStudy (amistre64):
good
now keep going
4 = y/25
OpenStudy (anonymous):
How do i find Y?
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OpenStudy (anonymous):
Would it be 5?
OpenStudy (amistre64):
is 5/25 = 4? no
OpenStudy (amistre64):
this is basic arithmetic ...
OpenStudy (amistre64):
multiply each side by ... what?
OpenStudy (anonymous):
4?
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OpenStudy (amistre64):
no .... at least not effectively
is 25/25 = 1?
OpenStudy (anonymous):
yes
OpenStudy (amistre64):
4 = y/25
4(25) = y(25/25)
this is 1
4(25) = y*1
what can we conclude?
OpenStudy (anonymous):
That y is 100?
OpenStudy (amistre64):
y is divided into 25 parts y/25 and
4 is equal to 1/25th of y
if we add up all 25 parts of y, we get 1 y ...
adding up 25 parts that are each equal to 4 is just: 4(25) = 100 yes
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