Question

Trig question.

Answer 1

So I already got the graph part correct. I just can't find the correct answers for the other two sections. (the correct graph is the left one)

Answer 2

k which part are we having trouble with? 0_o
the intersections?

Answer 3

Yeah the intersections.

Answer 4

@zepdrix :)

Answer 5

Err no maybe I'm counting wrong haha :)

Answer 6

ai, I can't get it haha

Answer 7

I thought it was up at 1, but it's clearly not 0_o woops.

Answer 8

I dunno, that's a weird question :o
isn't it just 0.5, 0.5 ... ish?

Answer 9

for the first box?

Answer 10

ya

Answer 11

err well I put 0.5, 0.58 because the (sqroot3/3) = 0.577

Answer 12

haha dude idk what they want D:

Answer 13

I dont understand.. this is so confusing..
are these two pages related to one another? 0_o

Answer 14

haha yeah xD the second picture goes first though

Answer 15

They intersect at \(\Large\rm f(x)=g(x)\) or at \(\large\rm \tan x=\frac{\sqrt3}{3}\), ya?

Answer 16

Which angle does this correspond to? :D

Answer 17

pi/6

Answer 18

Good! :)
So they intersect at x=pi/6, y=sqrt(3)/3.

Answer 19

wait, whaat, how did you do that? :P first box still , yeah?

Answer 20

f(x) = tan x.
g(x) = sqrt(3)/3.

We found the y coordinate of the intersection by setting these equal to one another.
f(x) = g(x) = sqrt(3)/3
So clearly our y-coordinate is sqrt(3)/3.

We did some fancy math to show that the angle, x, has to be pi/6 at this intersection.

Answer 21

ya first one :O

Answer 22

ook, so it would be (0.52,0.58) ??

Answer 23

ya that looks better i think :)

Answer 24

xD ok, hopefully that is correct :) on to box 2!

Answer 25

Algebraically, umm that's pretty much what we did.
We found that \(\Large\rm x=\frac{\pi}{6}\) in the small interval that they gave us.
Now for the second box, they've changed the interval to be from 0 to 2pi.

Answer 26

so ummm

Answer 27

Tangent is periodic in pi, so we'll get the same sqrt(3)/3 if we simply add pi to our angle x.

Answer 28

So \(\Large\rm x=\frac{\pi}{6}+\pi\) is also a solution in the interval 0 to 2pi.

Answer 29

So our x coordinate can be \(\Large\rm x=\frac{\pi}{6}+0\pi\) or \(\Large\rm x=\frac{\pi}{6}+1\pi\) ya?

Answer 30

ok. Those are the only two between 0 and 2pi?

Answer 31

Yes, our next one would be located at \(\Large\rm x=\frac{\pi}{6}+2\pi\) but that's clearly too large now.

Answer 32

But if they want the stupid k.. I guess we have to write it as,\[\Large\rm \left(\frac{\pi}{6}+k \pi,\qquad \right)\]Something like that, ya?
And we just have to remember that k=0 and k=1 are the only solutions in the interval 0 to 2pi.. because it doesn't look like they gave us a place to put that 0_o

Answer 33

Anddd the y-coordinate? :)

Answer 34

Do you understand how part (a) and part (b) relate to one another?
They're the same `values`, but (a) wanted them approximated.
So what should go in your y-coordinate slot this time? :)
Think back to part (a)

Answer 35

Er, still processing xD it was sqroot3/3

Answer 36

Good, that would be the `exact value`. Which is what they want in part (b).

Answer 37

\[\Large\rm \left(\frac{\pi}{6}+k \pi,~\frac{\sqrt3}{3} \right)\]Something like that for part (b), ya? :o

Answer 38

part a is weird to me... they want you to approximate the answer graphically. it is weird they require you to be accurate to two decimal places using that graph (it is very unzoomed in like)

Answer 39

^ lol ikr

Answer 40

Zepdrix, I guess? I'll try putting that in :)
@freckles I know! and there's a video thing that helps to solve it and it says "you can tell the two decimals by zooming in" but there's no zoom thing -.- what is this. haha

Answer 41

haha XD

Answer 42

they probably intend for you to use your own graphing calculator or something :)

Answer 43

ai, so part a is correct but part b they don't like D:

Answer 44

hmm

Answer 45

I think I have like 2 tries left 0_0

Answer 46

They want it in the form `x+pi k` not the form `x+k pi`.
Could it be that simple maybe?

Answer 47

hm, this is the video they give me for "helping to solve it" http://www.webassign.net/v4cgi/extra/bc_enhanced/index.tpl?asset=watch_it_player&asset_url=/bc_enhanced/sprecalc6_w_player/sprecalc6_07_05_037.html&UserPass=8a76a53e1e68d19b44aae9494c4a5f7f

Answer 48

woops +_+ your account, we can't get in hehe

Answer 49

aw shoot haha

Answer 50

Well, never mind xD

Answer 51

plan b. the first picture is their part a
the second pic is their part b

Answer 52

well
it says it wants it in the form
(x+pi*k, sqrt(3)/3)

where x is between 0 and 2pi

there are two solutions to tan(x)=sqrt(3)/3 on [0,2pi)
x=pi/6 or x=7pi/6

so it should be
(pi/6+pi*k,sqrt(3)/3) or (7pi/6+pi*k,sqrt(3)/3)
though this answer is totally repetitive

(pi/6+pi*k,sqrt(3)/3) should be all that is needed
but the way they say things makes me think they are looking for this
(pi/6+pi*k,sqrt(3)/3) or (7pi/6+pi*k,sqrt(3)/3)

before you enter in anything @Babynini
I would like to know if @zepdrix has any esp skills or better thoughts

Answer 53

ooh, you mean they might want both those answers for part b?

Answer 54

well it is stupid but yes
like they wanted the x-coordinate in the form x+pi*k where x is between 0 and 2pi
and there are two x's in between 0 and 2pi such that tan(x)=sqrt(3)/3


i say it is stupid because
all the values in pi/6+pi*k are also in 7pi/6+pi*k
for example,
if we have pi/6+pi*k where k=1
we have pi/6+pi=7pi/6 which is included in 7pi/6+pi*k for when k is 0

Answer 55

you know what maybe they are just being weird about the wording
and they just want (pi/6,sqrt(3)/3) or (7pi/6,sqrt(3)/3)

Answer 56

but I guess that one thing you posted is an example of what they want right?

Answer 57

Right, which is why I am confused haha because they're asking me to put it in all weird

Answer 58

and if it really is example
then this should have been correct:
\[(\frac{\pi}{6}+\pi \cdot k, \frac{\sqrt{3}}{3})\]

Answer 59

hmmm maybe they want parenthesis in there somewhere ?? perhaps it is being picky -.-

Answer 60

can you show a picture of exactly what you entered

Answer 61

oh my bad 0_o i ran off to get some foods.

Answer 62

and any messages they gave to correspond to the error you made when entering it

Answer 63

LOL zepdrix xD

Answer 64

K, I just put in (pi/6+k(pi), sqrt3/3)
notice, there is a () around the pi. and hallelujah it's correct now xP

Answer 65

Also, around the answer box there is a parenthesis that the program put there and I was putting a parenthesis around the whole thing and it didn't like that ._.

Answer 66

@Nnesha can you give freckles a medal please? :)

Answer 67

I don't need a medal. My cat pays me by the minute to help people in math because it struggles with math and it just wants other people to succeed in math where it cannot.

Answer 68

OH yah the first time you probably did something silly like this kpi
you need to input something to show that isn't one long word, like k*pi
brackets worked? yay

Answer 69

^^ xD your cat is the bomb.
Yep, just some parenthesis

Answer 70

the weird thing is these programs want you to have esp or whatever
it said it wanted the x-coordinate in the form x+pik
they didn't put a ( ) around the pi
it is all craziness to me

Answer 71

The programmers are old and lonely. They want to make our lives miserable. It's a conspiracy!

Answer 72

Wow, this question is the hang out spot. there's 7 people here :P

Answer 73

they are all waiting on more trig
people eat trig right on up like pie (not to be confused with the number pi of course)

Answer 74

yayyy mother's day \c:/
ooo crap, i gotta get mom something :o

Answer 75

oh yes, happy mothers day!!
Nicely done freckles, nicely done.

Answer 76

dude, get on that! I already got my mum something B) #aheadofthegame

Answer 77

here mum, have my homework!!

Answer 78

Ok yall, ready for question next?

Answer 79

XD

Answer 80

aaaand...closing this. Yall have been amazing :) don't forget your mums!