Help with Finding the Angle Between Two Lines
Find the angle between the following two lines: 2x + 3y = 5 x − 3y = 6
you know slope is a vector?
Yes so we have to put it into slope formula?
3y=x+6
1/3x+2=y
we dont 'have' to .... but it doesnt hurt if thats what you like
3y=-2x+5
oops meant y=-2/3x+2.5
ax + by = c by = -ax + c m = -a/b, for a vector of (b,-a)
2x + 3y = 5 (3,-2) x − 3y = 6 (-3,-1), or (3,1) (3,-2) ; sqrt(13) (3, 1) ; sqrt(10) ----------- 9-2 = 7 you know what to do with that
with this my book recommends me doing
which angle? |dw:1431311047079:dw|
yeah, if you want to go a non vector route, just thought you were playing wth vectors lately
ahh I see there are several methods here idk which is the best also brb
the best is the one that gets you to the solution in a manner that you are comfortable with. in programming its the one with the least number of computattions.
we need to define an inverse trig either way .... cos^(-1)(7/sqrt((13)(10)))
and that would give us the degrees for one ?
yeah, the other degree is 180 - that one ...
if we define the angle as the smallest angle, then if our results are >90, we subtract it from 180
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