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OpenStudy (darkbluechocobo):

Help with Finding the Angle Between Two Lines

OpenStudy (darkbluechocobo):

Find the angle between the following two lines: 2x + 3y = 5 x − 3y = 6

OpenStudy (amistre64):

you know slope is a vector?

OpenStudy (darkbluechocobo):

Yes so we have to put it into slope formula?

OpenStudy (darkbluechocobo):

3y=x+6

OpenStudy (darkbluechocobo):

1/3x+2=y

OpenStudy (amistre64):

we dont 'have' to .... but it doesnt hurt if thats what you like

OpenStudy (darkbluechocobo):

3y=-2x+5

OpenStudy (darkbluechocobo):

oops meant y=-2/3x+2.5

OpenStudy (amistre64):

ax + by = c by = -ax + c m = -a/b, for a vector of (b,-a)

OpenStudy (amistre64):

2x + 3y = 5 (3,-2) x − 3y = 6 (-3,-1), or (3,1) (3,-2) ; sqrt(13) (3, 1) ; sqrt(10) ----------- 9-2 = 7 you know what to do with that

OpenStudy (darkbluechocobo):

with this my book recommends me doing

OpenStudy (amistre64):

which angle? |dw:1431311047079:dw|

OpenStudy (amistre64):

yeah, if you want to go a non vector route, just thought you were playing wth vectors lately

OpenStudy (darkbluechocobo):

ahh I see there are several methods here idk which is the best also brb

OpenStudy (amistre64):

the best is the one that gets you to the solution in a manner that you are comfortable with. in programming its the one with the least number of computattions.

OpenStudy (amistre64):

we need to define an inverse trig either way .... cos^(-1)(7/sqrt((13)(10)))

OpenStudy (darkbluechocobo):

and that would give us the degrees for one ?

OpenStudy (amistre64):

yeah, the other degree is 180 - that one ...

OpenStudy (amistre64):

if we define the angle as the smallest angle, then if our results are >90, we subtract it from 180

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