how to get the parallel line of this? x=-9+6t y=6+7t z=3
strip off the direction vector
your coeffs of t define your direction vector
x=-9+6t y=6+7t z=3 + 0t
so is the parallel line the coefficients of t?
or the other ones?
no, the parallel part of the line is defined by the coeffs of t, we have to anchor it to a point for it to define a line
|dw:1431318634923:dw|
ok can you teach me what to do
strip .... off ... the coeffs .... of t what is it you are trying to do?
there are many parallel lines to your given line
oh sorry yeah i already got the answer thanks!
you said find *the* parallel line?
the whole question was find the distance etc etc
im going to go out on a limb and say that wasnt the whole question :) but good luck
sorry for the mistake i thought it wouldnt make a difference thanks anyway i got it
amistre , just checking, the set of parallel lines is x=a+6t y=b+7t z=c
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