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Mathematics 11 Online
OpenStudy (anonymous):

a 154 lb person burns 420calories per hour riding an exercise bicycle at a rate of 15 mi/hr write a function rule to represent the total calories burned over time by that person. Explain how the information in the problem relates to the function. ?

OpenStudy (anonymous):

can some help me?

OpenStudy (anonymous):

Don't ask for help on other peoples questions. I can not help you.

OpenStudy (anonymous):

well this is like building a distance time graph you have to know what is the independent variable and the dependent variable

OpenStudy (anonymous):

Don't you have to write a function rule...?

OpenStudy (anonymous):

yup but before you write a function rule you must picture out a graph (which IS itself a function) and for that you have to know what is dependent and what is independent

OpenStudy (anonymous):

in this question you can forget about the rate and the person's weight

OpenStudy (anonymous):

the time and the calories burned?

OpenStudy (anonymous):

exactly so according to your common who is depending on who? the calories are depending on the time or the other way around?

OpenStudy (anonymous):

*common sense

OpenStudy (anonymous):

if the guy doesn't spend time exercising he's not gonna lose calories, now is he?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

So the calories depend on the time

OpenStudy (anonymous):

@nopen

OpenStudy (anonymous):

Oh sorry my OS is lagging again =_=

OpenStudy (anonymous):

Yup Now if you're familiar Y is always the dependent variable and x is independent variable

OpenStudy (anonymous):

So since they said its 420 calories per hour Then it should be 420 * t For any given hour

OpenStudy (anonymous):

Where t is time

OpenStudy (anonymous):

So y = 420*t

OpenStudy (anonymous):

That is our range And our domain is t

OpenStudy (anonymous):

So far so good?

OpenStudy (anonymous):

@samsteronbroadway ?

OpenStudy (anonymous):

SO SORRY IT WAS LAGGING I COULDN'T READ IT @nopen

OpenStudy (anonymous):

Yes is that it?

OpenStudy (anonymous):

yup C(t) = 420*t

OpenStudy (anonymous):

wait so c(t)= 420t? or y=420t? @nopen Thanks so much!

OpenStudy (anonymous):

yes it's c(t) = 420t

OpenStudy (anonymous):

lol I wasn't sure so I deleted my answer hahaha nice @nopen

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