Match the functions to their ranges.
y= 3 sin(x-pi)
y=1-sin(x)
y=3+4cos(x-pi)
y=2+cot(x)
(-infinity, infinity)
[-1, 7]
[-3, 3]
[0, 2]

Question

Match the functions to their ranges.
y= 3 sin(x-pi)
y=1-sin(x)
y=3+4cos(x-pi)
y=2+cot(x)
(-infinity, infinity)
[-1, 7]
[-3, 3]
[0, 2]

xapproachesinfinity · Answer

let's take the first one
$$y=3\sin(x-\pi)$$
we know that sin is always btw -1 and 1
so $$-1\le\sin(x-\pi)\leq1$$
multiply by 3
$$-3\le y\le 3$$
$$\therefore ~~Range ~is~~[-3,3]$$

xapproachesinfinity · Answer

repeat the same idea with others

anonymous · Answer

@xapproachesinfinity  i have no idea what you did there...

xapproachesinfinity · Answer

all i did is i used our knowledge that sin and cos always trapped btw -1 an 1
ever seen the graph of sin a cos pay attention to them

xapproachesinfinity · Answer

then i multiplied by 3
so i get my functions range

anonymous · Answer

do i always multiple by 3. ?

anonymous · Answer

@xapproachesinfinity

xapproachesinfinity · Answer

no depends on the function you have
that one has 3 to it
but other will be different

anonymous · Answer

okay, then i don't know what im doing. so im going to guess. lol