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OpenStudy (anonymous):
jigglypuff314 (jigglypuff314):
try using the Pythagorean theorem on each on :)
a^2 + b^2 = c^2
if you get something like 3=3 then it IS a right triangle
if you get something like 0=3 (not a true statement) then it is NOT a right triangle
OpenStudy (anonymous):
do u have time for more?
jigglypuff314 (jigglypuff314):
sure
OpenStudy (anonymous):
Solve for x.
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jigglypuff314 (jigglypuff314):
from...?
OpenStudy (anonymous):
jigglypuff314 (jigglypuff314):
the longer way of doing this is to multiply both sides by 2
so you get 2*(2/x) = 6
then multiply both sides by x
so you get 2*2 = 6*x
can you solve for x from there? :)
OpenStudy (anonymous):
so would it be 2/3?
jigglypuff314 (jigglypuff314):
yes :)
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OpenStudy (anonymous):
thank you ^.^
OpenStudy (anonymous):
and i need to find x again
jigglypuff314 (jigglypuff314):
same idea ^_^
multiply both sides by 3
then multiply both sides by 8
OpenStudy (anonymous):
8/15
1 7/8
4 4/5
OpenStudy (anonymous):
so the first one /.\
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jigglypuff314 (jigglypuff314):
hmmm not quite ^_^
it seems to be a little upside down? .-.
8*x = 3*5
OpenStudy (anonymous):
Find the ratio of x to y.
OpenStudy (anonymous):
so the second one cx
jigglypuff314 (jigglypuff314):
yah :)
jigglypuff314 (jigglypuff314):
now this one is a little more complicated, you just have to take it apart a little by little :)
x 2
- = --
5 3
try solving for x from there
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