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Mathematics 10 Online
OpenStudy (anonymous):

Which of the triangles are right triangles?

OpenStudy (anonymous):

jigglypuff314 (jigglypuff314):

try using the Pythagorean theorem on each on :) a^2 + b^2 = c^2 if you get something like 3=3 then it IS a right triangle if you get something like 0=3 (not a true statement) then it is NOT a right triangle

OpenStudy (anonymous):

do u have time for more?

jigglypuff314 (jigglypuff314):

sure

OpenStudy (anonymous):

Solve for x.

jigglypuff314 (jigglypuff314):

from...?

OpenStudy (anonymous):

jigglypuff314 (jigglypuff314):

the longer way of doing this is to multiply both sides by 2 so you get 2*(2/x) = 6 then multiply both sides by x so you get 2*2 = 6*x can you solve for x from there? :)

OpenStudy (anonymous):

so would it be 2/3?

jigglypuff314 (jigglypuff314):

yes :)

OpenStudy (anonymous):

thank you ^.^

OpenStudy (anonymous):

and i need to find x again

jigglypuff314 (jigglypuff314):

same idea ^_^ multiply both sides by 3 then multiply both sides by 8

OpenStudy (anonymous):

8/15 1 7/8 4 4/5

OpenStudy (anonymous):

so the first one /.\

jigglypuff314 (jigglypuff314):

hmmm not quite ^_^ it seems to be a little upside down? .-. 8*x = 3*5

OpenStudy (anonymous):

Find the ratio of x to y.

OpenStudy (anonymous):

so the second one cx

jigglypuff314 (jigglypuff314):

yah :)

jigglypuff314 (jigglypuff314):

now this one is a little more complicated, you just have to take it apart a little by little :) x 2 - = -- 5 3 try solving for x from there

OpenStudy (anonymous):

the 1st one

jigglypuff314 (jigglypuff314):

*blinks* what first one? :P

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