Question

(cosecA-sinA)(secA-cosA)(tanA+cotA) = 2

Answer 1

@triciaal

Answer 2

you want to prove this right?

Answer 3

LHS = RHS

Answer 4

convert to sin's and cos

= ( 1/s - s)(1/c - c)( s/c + c/s)

= 1 -s^2 1 - c^2 s^2 + c^2
------ * ------- * ---------
s c cs

now c^2 + s^2 = 1 and 1 - s^2 = c^2 and 1 - c^2 = s^2

so we have
c^2/s * s^2/c * 1/ cs

= c^2 s^2 / c^2 s^2 = 1

Answer 5

I make it 1
either i've made a mistake or question is wrong...

Answer 6

Yes,It's 1 and not 2

Answer 7

i expet you might now this by i used the identities sec x = 1/cos x , cot x = 1/tan x and cosex x = 1 / sin x