Question

Can somebody tell me if I'm right?

Given f(x) = 4x+1/3, solve for f-1(3)

I got 2

The answer choices are
2
4
6
8

Answer 1

4x+1/3
or
(4x+1)/3

?

Answer 2

4x+1 over 3
Kinda like a fraction :)

Answer 3

Can you explain to me how it's 4? :)

Answer 4

so you mean (4x+1)/3 ?

\[f^{-1}(3)=a \\ \text{ then } f(a)=3 \\ \text{ so solve } \frac{4a+1}{3}=3 \]

Answer 5

can you finish solving 4a+1=9

Answer 6

Yes but there are no parenthesis

Answer 7

Here

Answer 8

(4x+1)/3
means
\[\frac{4x+1}{3}\]
where as 4x+1/3
means
\[4x+\frac{1}{3}\]

Answer 9

yes I made that assumption above

Answer 10

\[f^{-1}(3)=a \\ \text{ then } f(a)=3 \\ \text{ so solve } \frac{4a+1}{3}=3 \]
I was asking you to solve this for a
to verify your answer

Answer 11

multiply 3 on both sides
4a+1=9

and 2 more steps and you will have your answer

Answer 12

4a=8
Divide by 4
=2?

Answer 13

yep