Question

Help me for a derivative as tangent problem

Answer 1

I'll post the problem

Answer 2

Determine the numbers x between 0 and \[2\pi\] where the tangent line in the curve is horizontal.
given:
\[y=sinx-\sqrt{3}cosx\]

Answer 3

Refer to a plot and the Mathematica solution attached.

Answer 4

wow thanks! even though we haven't discussed partial derivatives yet, I will try to understand.

Answer 5

When tangent line in the curve is horizontal, it is =0
hence, \( cos x + \sqrt 3 sin x=0\rightarrow \dfrac{sinx}{cosx}=-\sqrt3 \\tanx = -\sqrt3 \)
you can solve for x, right?

Answer 6

The partial derivative of an expression in x alone, with respect to x, is equivalent to
the plain old derivative of x. I use the partial notation because it is more concise in
the Mathematica 9 program.