Question

2x^2 - 5x - 3 = 0

Answer 1

@thomas5267

Answer 2

\[ax^2+bx+c=0\]
Apply the quadratic formula
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 3

Umm?
I can only use the formula when its mentioned in the question,Over here it's not so I HAVE to factor it.

Answer 4

oh, ok

Answer 5

\[2x^2-5x-3=0\]
the factored form will have to be some thing like this
\[(2x+\dots)(x+\dots)=0\]
right?

Answer 6

???

Answer 7

Is x = 3?

Answer 8

that is one of the solutions

Answer 9

and -1/2?

Answer 10

yes, (im not sure how you got them, though)

Answer 11

So what is the factored form of the equation?

Answer 12

(2x - 1)(x - 3) = 0

Answer 13

almost, but not exactly

Answer 14

notice how -1 times -3 would give +3

Answer 15

we want -3, so they can't both be negative signs

Answer 16

Oops ,.Typo it's (2x + 1)

Answer 17

Can you help me a bit more?
And Thanks.

Answer 18

yep!, but how did you find those solutions, did you perform long division or something?

Answer 19

My methods(They are valid according to my teacher)
And what's "long division"???

Answer 20

never mind "long division", it's horrible