Solve the equation using he Quadratic Formula x^2 - 7x -3=0
list your a b c values :)
Ok what else I did that ?
well then we plug them in
First tell me what they are
\[ax^2+bx+c\]
Once you have the values you plug them in this formula \[x=\frac{-b ± \sqrt(b^2 - 4ac) }{ 2a }\]
A: x B:-7 C:-3
\[\rm x=\frac{-b ± \sqrt{(b^2 - 4ac)} }{ 2a }\] now plug it in
\[\rm x=\frac{-(-7) ± \sqrt{(-7)^2 - 4(1)(-3)} }{ 2(1) }\]
From there all you do is solve
Okay do I multiply or divide
fist solve whats in the square root but do not square root it just do it as an equation
ok let try to solve it
is the answer -1
then I divide by the bottom
no its not
\[\rm x=\frac{7 ± \sqrt{61} }{ 2 }\] now to solve it all you do is set up 2 equations \[\rm x=\frac{7 +\sqrt{61} }{ 2 }\] \[\rm x=\frac{7 - \sqrt{61} }{ 2 }\]
Then you solve.
do i square root 61?
yes
http://www.math.com/students/calculators/source/quadratic.htm i suggest using that instead of trying to calculate it by hand
ok thank you
No problem.
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