Solving one triangle using two?
so you can use the pythagorean to find either a or b |dw:1431813801877:dw| then proceed from there
I know a^2+b^2=c^2 But.. How do you do about only knowing c^2? They make sure to only give you 2 details about both triangles, so you can't solve one and figure out the other. Gah. I just need a hand to move forward. ><"
What class is this for btw?
Geometry ><"
I don't want the actual answer, I just need a hand going about getting another number so I can solve it. I didn't post what A B C or D was for a reason..!
you're rigth about that, i didn't notice.. maybe you can use some sort of ratio? let me seee
how about if u post A , B C or D bec sometimes good to solve a question backwards :D :D js
|dw:1431814920638:dw| \(tan(\theta)=\dfrac{12}{x}\) \(tan(90-\theta)=\dfrac{21}{x}\) maybe from here make some substitutions?
I would rather know how to work about doing it without going backward, for the sake of possibly not having the answers next time.
nobody is going to give u a direct answer i said that for some reason it's a math we have to play with numbers i was saying some time it helps anyways good luck thanks
|dw:1431815246279:dw|
Pythagorean in ABD to Pythagorean in BDC Pythagorean in ABC you can find x Need more guidance, just let me know
knock knock!!! can't step up??
Ohhhh, yeah that made it obvious! |dw:1431815689053:dw|
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