ΔABC is translated 6 units up and 3 units left to create ΔA′B′C′. If vertex A is located at (-1, 2), what are the coordinates of A′ ? PLEASEE HELP!!

Question

ΔABC is translated 6 units up and 3 units left to create ΔA′B′C′. If vertex A is located at (-1, 2), what are the coordinates of A′ ?  PLEASEE HELP!!

anonymous · Answer

okay so graphing this will help A LOT

anonymous · Answer

(5, -1)
(-4, 8)

(2, -4)

(-7, -1)

anonymous · Answer

graph the point A (-1,3).. then from there move the point up 6 and left 3 units. then you will get its new location.

anonymous · Answer

i think it's b

anonymous · Answer

youre correct i believe its B

misty1212 · Answer

$$(\overbrace{x}^{\text {left right}},\overbrace{y}^{\text{up down}})$$

misty1212 · Answer

yeah B what you said!

anonymous · Answer

yes ! i got it! i thank you both !

anonymous · Answer

Polygon ABCD will be dilated by a factor of 2 to produce polygon A′B′C′D′. The origin is the center of dilation. Which point will not represent a vertex on polygon A′B′C′D′ ?

anonymous · Answer

would yall happen to know this one ?