what is the probability that five different books randomly arranged on a bookshelf are in alphabetical order?

Question

anonymous · Answer

Using Basic Probability Properties

mathstudent55 · Answer

Find how many desired outcomes there are vs how many total outcomes there are.

mathstudent55 · Answer

There is only one desired outcome. The books are in alphabetical order.
How many total outcomes are there? In how many ways can you place 5 different books on a shelf?

anonymous · Answer

@mathstudent55 it's asking what probability of that happening is not how many outcomes

misty1212 · Answer

HI!!

misty1212 · Answer

that is  your denominator
1 is the numerator

anonymous · Answer

I've tried that but I keep getting 0.00833.... 

Do I put 5! as the denominator or just 5?
If I put just 5 then I get 20%

mathstudent55 · Answer

There is one single desired outcome. that the books be in alphabetical order.
How many total outcomes are there? In how many ways can they be arranged?

Then P(alphabetical order) = 1/(total number of way of arranging the 5 different books)

anonymous · Answer

@misty1212

mathstudent55 · Answer

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