Which logarithmic function has x = 5 as its vertical asymptote and (6, 0) as the x-intercept? (x is the variable.) The logarithmic function is f(x) = log ?
Well, a normal log(x) has a vertical asymptote at x=0, right?
To get the log function to have a vertical asymptote at x=5 all we have to do is shift it five units to the right.
so f(x)= log(x-5)
the reason it is minus five is because vertical and horizontal shifts the affect the x variable are always the opposite operation.
f(x) = log(x-5) automatically has 6 as its x-intercept as well, because log(6-5)=log(1)=0
not vertical
yes, since you are shifting the whole graph five units to the right , and the original log(x) had an x-int at (1,0), the x-int is also shifted five units to the right as well.
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