Question

Can someone check my work? I will give a medal.

Answer 1

ok

Answer 2

Verify the basic identity. What is the domain of validity?

cos(theta)=cos(theta)csc(theta)


I got it to cos(theta)/sin(theta)=cos(theta)/sin(theta)

I don't know how to find the domain of validity though

Answer 3

well, for all values that cos(\(\theta\))=0, or csc(\(\theta\))=1 ... but sin(\(\theta\))\(\ne\)0, because otherwise the result is undefined for the cosecant.

Answer 4

csc( theta) = 1/sin(theta)

Answer 5

so
cos(theta)=cot(theta)

Answer 6

at (pi/2)*n where is 1,2,3,4,....

Answer 7

both cos(theta)=cot(theta)=0

Answer 8

Wait so was my answer right?

Answer 9

Was i not done verifying... I though i was fine with that, I just did not know how to do the domain

Answer 10

@SolomonZelman

Answer 11

domain of validity is just the solution... (or solution(s) )