Please help me, I will give medal:)
The value of y varies directly with x^2(x squared),and y=150 when x=5.What is the value of y when x=3?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
as this is direct variation we can write
y = k x^2 where k is a constant
OpenStudy (anonymous):
ok, so would I square 3?
OpenStudy (welshfella):
given that y = 150 when x = 5:-
150 = k * 5^2
can you work out what k is ?
OpenStudy (anonymous):
ummmm, no :(
OpenStudy (welshfella):
leave the squaring of 3 until later
the first part of the solution is to find the value of k
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
5^2 = 25 right?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so that would be K?
OpenStudy (welshfella):
ok so we have 25k = 150
and to find k we divide both sides by 25
so k = 150 /25 = ?
OpenStudy (anonymous):
6
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (welshfella):
right now we have the values of k
k is called the constant of variation
now we have established the relationship between y and x
it is
y = 6x ( replacing k by 6)
OpenStudy (welshfella):
now we can answer the quest ' What is y when x = 3
OpenStudy (welshfella):
oops sorry
thats y = 6x^2 not 6x
OpenStudy (anonymous):
y=9?
OpenStudy (welshfella):
so when x = 3
y = 6 * (3)^2
Still Need Help?
Join the QuestionCove community and study together with friends!