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given sin(theta)=12/13, find sec(theta) a.)sec(theta)=13/12 b.)sec(theta)=13/5 c.)sec(theta)=5/13 d.)sec(theta)=5/12
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|dw:1431985831090:dw|
So no we can see cos(theta) = 5/13 And since we know \(\large sec(\theta) = \frac{1}{cos(\theta)}\) ...
my brain just died hun xD
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