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Mathematics 11 Online
OpenStudy (anonymous):

Need Help What is the solution to the equation? http://static.k12.com/bank_packages/files/media/3340584df18a5a895ea43589cea9b06a.png Choose all answers that are correct. http://static.k12.com/bank_packages/files/media/5236e1a1d63724c08fb74b1c09bc2224.png http://static.k12.com/bank_packages/files/media/d32cdfe19430355de699d2997f410327.png http://static.k12.com/bank_packages/files/media/4d4bf60e2ebd9e0cb7f217c72c870118.png http://static.k12.com/bank_packages/files/media/30ecef34e23508c8d0bc8d2aa83a9fd7.png

jagr2713 (jagr2713):

Ok what do you think we do so?

OpenStudy (anonymous):

I was thinking that to you square root the number then multiply it by the number on the outside

jagr2713 (jagr2713):

Nope we add 3 on both sides first right? and what do we get?

OpenStudy (anonymous):

for the first one i got 8 \[\sqrt{5}\]

OpenStudy (anonymous):

Is that what you meant?

jagr2713 (jagr2713):

77+3=80 right so we get \[4x ^{2}=80\]what do we do next

OpenStudy (anonymous):

We Solve for x?

jagr2713 (jagr2713):

Nope what do we Do with the 4

OpenStudy (anonymous):

i think we cancel it out

jagr2713 (jagr2713):

kinda we divide right? we are left with?

OpenStudy (anonymous):

20?

jagr2713 (jagr2713):

Yes so \[x ^{2}=20\]whats next ?

OpenStudy (anonymous):

Would we try to find x?

jagr2713 (jagr2713):

No we take the square root of both sies \[x=\pm \sqrt{20}\]

jagr2713 (jagr2713):

whats next?

OpenStudy (anonymous):

we square root 20

jagr2713 (jagr2713):

which is?

OpenStudy (anonymous):

4.472135

jagr2713 (jagr2713):

ohh sorry we simplify and get?

OpenStudy (anonymous):

4.5?

jagr2713 (jagr2713):

what to numbers goes into 20

jagr2713 (jagr2713):

2 is one right? whats the next one

OpenStudy (anonymous):

1,4,5,10, and 20

jagr2713 (jagr2713):

pick one, which one do we always use

OpenStudy (anonymous):

4

OpenStudy (anonymous):

or 5

jagr2713 (jagr2713):

Yes 5 so the answer is ?

OpenStudy (anonymous):

5?

jagr2713 (jagr2713):

and? i said it above

OpenStudy (anonymous):

and 2

jagr2713 (jagr2713):

So we get for the answer?

OpenStudy (anonymous):

A and D

jagr2713 (jagr2713):

Nope the 2 was first

jagr2713 (jagr2713):

we get \[x=\pm2\sqrt{5}\]

OpenStudy (anonymous):

oh B and C

jagr2713 (jagr2713):

Which one

OpenStudy (anonymous):

both

jagr2713 (jagr2713):

Nope pick one b.c we have \[\pm \]

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