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What is the solution to the equation?
http://static.k12.com/bank_packages/files/media/3340584df18a5a895ea43589cea9b06a.png
Choose all answers that are correct.
http://static.k12.com/bank_packages/files/media/5236e1a1d63724c08fb74b1c09bc2224.png
http://static.k12.com/bank_packages/files/media/d32cdfe19430355de699d2997f410327.png
http://static.k12.com/bank_packages/files/media/4d4bf60e2ebd9e0cb7f217c72c870118.png
http://static.k12.com/bank_packages/files/media/30ecef34e23508c8d0bc8d2aa83a9fd7.png
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jagr2713 (jagr2713):
Ok what do you think we do so?
OpenStudy (anonymous):
I was thinking that to you square root the number then multiply it by the number on the outside
jagr2713 (jagr2713):
Nope we add 3 on both sides first right? and what do we get?
OpenStudy (anonymous):
for the first one i got 8 \[\sqrt{5}\]
OpenStudy (anonymous):
Is that what you meant?
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jagr2713 (jagr2713):
77+3=80 right so we get
\[4x ^{2}=80\]what do we do next
OpenStudy (anonymous):
We Solve for x?
jagr2713 (jagr2713):
Nope what do we Do with the 4
OpenStudy (anonymous):
i think we cancel it out
jagr2713 (jagr2713):
kinda we divide right?
we are left with?
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OpenStudy (anonymous):
20?
jagr2713 (jagr2713):
Yes so \[x ^{2}=20\]whats next ?
OpenStudy (anonymous):
Would we try to find x?
jagr2713 (jagr2713):
No we take the square root of both sies
\[x=\pm \sqrt{20}\]
jagr2713 (jagr2713):
whats next?
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OpenStudy (anonymous):
we square root 20
jagr2713 (jagr2713):
which is?
OpenStudy (anonymous):
4.472135
jagr2713 (jagr2713):
ohh sorry we simplify
and get?
OpenStudy (anonymous):
4.5?
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jagr2713 (jagr2713):
what to numbers goes into 20
jagr2713 (jagr2713):
2 is one right? whats the next one
OpenStudy (anonymous):
1,4,5,10, and 20
jagr2713 (jagr2713):
pick one, which one do we always use
OpenStudy (anonymous):
4
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OpenStudy (anonymous):
or 5
jagr2713 (jagr2713):
Yes 5 so the answer is ?
OpenStudy (anonymous):
5?
jagr2713 (jagr2713):
and? i said it above
OpenStudy (anonymous):
and 2
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jagr2713 (jagr2713):
So we get for the answer?
OpenStudy (anonymous):
A and D
jagr2713 (jagr2713):
Nope the 2 was first
jagr2713 (jagr2713):
we get
\[x=\pm2\sqrt{5}\]
OpenStudy (anonymous):
oh B and C
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