Question

logarithms? help please

Answer 1

no idea how to even start solving this... :/

Answer 2

Write the entire right side as single log.

Answer 3

log2(a + b - c)??

Answer 4

No.
The sum of logs is a product.
The difference of logs is a division.

Answer 5

ab/c?

Answer 6

\(\log a + \log b = \log (ab)\)

\(\log a - \log b = \log \dfrac{a}{b} \)

Answer 7

Correct.

Answer 8

ooh so x = ab/c?

Answer 9

\(\log_2 x = \log_2 a + \log_2 b - \log_2 c\)

By writing a single log ion the right side, you get:

\(\log_2 x = \log_2 \dfrac{ab}{c} \)

Now there is a rule:

If \(\log_b x = \log_b y\), then \(x = y\).

In your case, then,

\(x = \dfrac{ab}{c} \)

Answer 10

You are correct.

Answer 11

thank you for the help :_

Answer 12

oops :) *

Answer 13

You're welcome.

Answer 14

Oh I missed out. :(