Question

Can someone check my stats answer please?

Answer 1

thats just awful ... hurts my eyes

Answer 2

you have 2 data sets

Answer 3

you dont stray to far from 2.3, so the mean cant be 4.6

and the max cant be 23

Answer 4

oops sorry i pasted the wrong thing, this is what i got:
Minimum= 2.29816
Maximum: 2.30182
1st quartile= 2.29874
Median= 2.29915
3rd quartile= 2.30069

Answer 5

@amistre64

Answer 6

for which set?

Answer 7

the first one

Answer 8

now, min and max ive read as 2 different things. how does your course define them?

Answer 9

minimum= the smallest observation in the data set
maximum= the greatest observation in the data set

Answer 10

1 229816, q0
2 229849,
3 229869, q1
4 229889,
5 229890,
915 median q2
6 229940,
7 230054,
8 230074, q3
9 230143,
0 230182 q4

Answer 11

some ive seen define it as (q1,q3) +- IQR(1.5)

Answer 12

hmm ok, i just typed what my textbook said but i still could've done something wrong

Answer 13

or rather, if half the normal data is between the range of q1 and q2, then 100% of the normal data should be within twice the IQR ....

Answer 14

no, im with you on min and max, low and high

Answer 15

oh ok, i have IQR defined as: the range between the upper and lower quartiles, Q3-Q1. This range contains the middle 50% of the observations in the data set.
Lower quartile (Q1): the number that is greater than or equal to 25% of the observations in a numeric data set.
Upper quartile (Q3): The number that is above or equal to 75% of the observations in a numeric data set

Answer 16

yep

but our numbers arent matching

Answer 17

some are

Answer 18

how do you do your calculations?

Answer 19

i entered them into my calculator in L1 and L2 but i could've easily done it wrong

Answer 20

lots of numbers to keep track of, and the decimal point is not required.

Answer 21

also, the ti83 might have a different algorithm for the quartiles. there is one that is more interpolation than the one I was taught. I was taught

n/4 and rnd up to the nearest integer for position.

Answer 22

10*1/4 = 2.xxx = 3

10*2/4 = 5, average 5 and 6

10*3/4 = 7.xxx = 8

Answer 23

oh ok i think we got the same thing now i got , now I'm getting min= 2.29816, 2.29869, median= 2.29915, third quartile= 2.30074, maximum= 2.30182

Answer 24

1 229816, q0
3 229869, q1
915 median q2
8 230074, q3
0 230182 q4

yep

Answer 25

and the mean?

Answer 26

2.299706

Answer 27

@amistre64
min= 2.29816, median= 2.29915, third quartile= 2.30074, maximum= 2.30182

i got the mean mean= 2.299706
can you tell me if i got it right please?