Caley has a bag that contains 9 blue marbles and 13 yellow marbles. She selects a marble at random, and then, without replacing the first one, selects another marble at random. What is the probability that Caley selects a blue marble and then a yellow marble? Round your answer to the nearest percent. P(blue and yellow) ≈ %
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what the probability of picking a blue marble first?
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it need to be shortend like 0.2
The probabilty of the second pull is effected by the results of the first, so we have to work out the probability of dependant events. P(A|B) = P(AnB)/P(B) therefore, P(AnB) = P(B) P(A|B)
its not that practical at this stage, but what it mean is: the probability of the first pull, times the adjustment for the second pull is what we are looking for
P(blue first) = #blue, divided by # marbles P(yellow second) = #yellow remaining, divided by # of all marbles remaining.
so the answer is 25
no how many blue marbles are there to start with? and how many marbles are there altogheter to start with?
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