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Mathematics 10 Online
OpenStudy (anonymous):

WILL FAN AND MEDAL!!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

300,000

OpenStudy (joannablackwelder):

Do you know the relationship between distance, rate, and time?

OpenStudy (anonymous):

(3.00*10^8)(3.54*10^7)

OpenStudy (campbell_st):

this uses the formula \[Speed = \frac{distance~~travelled}{time ~taken}\] you have the distance and the speed so \[Time ~taken = \frac{distance~ travelled}{time~taken}\]

OpenStudy (campbell_st):

hope it helps

OpenStudy (joannablackwelder):

@campbell_st is correct. The general formula is distance=rate*time

OpenStudy (campbell_st):

oops should read \[time ~taken = \frac{distance}{speed}\]

OpenStudy (anonymous):

@Kitten_is_back

OpenStudy (kitten_is_back):

:D i think they got it:)

OpenStudy (anonymous):

that is not what it wants ex. 3.54*10^15

OpenStudy (kitten_is_back):

never mind

OpenStudy (kitten_is_back):

add you're two sums love

OpenStudy (anonymous):

6.54*10^15

OpenStudy (anonymous):

did i get it right @Kitten_is_back

OpenStudy (joannablackwelder):

No

OpenStudy (joannablackwelder):

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