Question

Reduce to lowest terms.
https://clackamasweb.owschools.com/media/g_ima01_2014/2/test3.gif

-4x^3 y^2
-2x^2 y^2
-1/2x^2 y^2

Answer 1

@geerky42

Answer 2

\[\dfrac{4x^3y^4}{-8xy^2} = -\dfrac{4}{8}\cdot\dfrac{x^3}{x}\cdot\dfrac{y^4}{y^2}\]

You can use this exponent rule: \(\dfrac{a^b}{a^c} = a^{b-c}\)

Answer 3

so its the second one? @geerky42

Answer 4

thank you

Answer 5

Almost. What is -4/8?

Answer 6

-4/8 = -1/2, right?

Answer 7

yep

Answer 8

so its the last one?